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#1 |
Special Member
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This a question I've never gotten an answer too. My power amp has buttons for "A" speakers and "B" speakers. It's a 100w * 2 power amp. Now if I use either A or B I understand I'm getting 100w per channel to which ever set I'm connecting. What if I run both A and B at the same time?
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#4 | |
Blu-ray Champion
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![]() Quote:
Series Loudspeakers: ![]() This connection would give a final impedance of 8 ohms. Parallel Loudspeakers: ![]() This connection would give a final impedance of 2 ohms. Nad Borchure: http://www.nadelectronics.com/img/da...s/NAD_2400.pdf Go to the bottom and see information: http://cgi.ebay.com/NAD-2400-PE-THX-...d=p3286.c0.m14 Last edited by Big Daddy; 12-30-2009 at 12:39 AM. |
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#5 |
New Member
Dec 2009
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I s there a problem to cross the outputs AR + BL or AL + BR, with the amp switched to A+B all the time.
Is the amp working twice as much in this way (with 2 channels having no load)? Is there a problem if it has no speakers to send the signal to? Thanks! Last edited by sorrell; 12-29-2009 at 12:41 PM. Reason: Update |
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#6 |
Blu-ray Champion
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In most cases, there should not be a problem with no load.
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#7 |
Member
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An additional question regarding this topic.
could i technically bridge the A+ and A- with B+ and B- of the Left and Right Channels? would it be a moot point putting them together or would i actually use both channels to push to the front speakers? Additioanlly, could i use front A as highs and front B as Low's for Bi-wiring, or am i reaching a bit too far? visual: ___________________________ l LA+ LA- l l I I l l LB+ LB- l l l l RA+ RA- l l I I l l RB+ RB- l l__________________________l EDIT, that should be bigger spaces, but the I's are representing bridges between the A and B setups Last edited by JJJMan; 12-30-2009 at 06:13 PM. |
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#8 | |
Blu-ray Champion
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![]() Quote:
Bridging refers to combining two channels of an amplifier into one with twice the voltage. A two channel amp can be bridged to one channel, and a four channel amp into two channels. Bridging the channels increases the power output. An amplifier is usually bridged to combine two channels to power one speaker/subwoofer, or to combine four channels into powering two speakers/subwoofers. It is common to bridge the power amplifier to increase the power available and generate more output from the sound system. This may be appropriate with a passive subwoofer. However, if you are dealing with full range speakers, it may be more appropriate to bi-amp them. Bridgeable amplifiers are designed with an inverted channel for bridging purposes. The inverted channel produces voltage that is generated at the opposite polarity of the un-bridged channel. Sometimes your amp will have a diagram for bridging. For example, look at the far right of the following 4-channel amplifier for bridging diagram. ![]() If your amp is not able to bridge, you may still be able to do it with a DIY bridging adapter, but Before you attempt to bridge an amplifier, there are certain things you must keep in mind. Only bridge an amplifier that can handle the increased power load. Do not bridge an amp that will be unstable at the bridged load. To understand how to bridge an amplifier that is not bridgeable, read these articles. http://sound.westhost.com/project20.htm http://sound.westhost.com/project14.htm http://www.yamaha.com/yamahavgn/CDA/...402340,00.html ![]() ![]() Bridging an amplifier produces twice the voltage and four times the power as it would in an un-bridged status. As an example, consider a 50 Watt per channel amplifier into 8 Ohms. This amplifier requires a signal voltage of 20 Volts RMS per channel to generate 50 watts per channel: P = V^2 / R = (20)^2 / 8 = 400 / 8 = 50 Watts The same amplifier into 4 Ohms will deliver close to 100W - provided the power supply can remain stable under the load. If the two-channel amplifier is bridged into a single channel, the 8 Ohm loudspeaker now sees double the voltage. Using the formula above, we get: P = V^2 / R = (40)^2 / 8 = 1600 / 8 = 200 Watts |
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#9 |
Member
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oh, ok, thank you BigDaddy, i see what you're saying now, i've bridged a 2 channel amp into a single sub before, just forgot how to do it.
so what i'm wanting to do, is take the RightFrontA+ and the RightFrontB- to sent to the right speaker to get the wattage from both A and B channels, same with LeftFrontA+ and LeftFrontB-. In my head what im saying makes perfect sense haha. |
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