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#17 | |
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![]() Quote:
![]() Squares and Viewing Distance: 720p is about 1,000,000 pixels and 1080p ~2,000,000, so 1080p is 2x over 720p. 1/2 +1/2 = 1 in a linear realtionship, as in a number line, which are powers of 1. But we are dealing with an area which is a power of 2. So there would actually be four 1/2" squares fitting inside 1" squares on the graph paper, suggesting 1080p is 4x over 720p, which it is not. Look at the image below of a 4X4 image upscaled to 8X8. You can also see why I would rather convert 480p to 960p with black bars on all 4 sides of the image rather then filling entire screen of a 1080p set. Square Numbers The Number Line Cartesian Coordinates To get two equal squares to exactly fill the area of a larger square, we have the formula for doubling a square with side of length 'a' for a square of length 'x': x^2 = 2a^2 However, the idea of squares is interesting. If you are at some optimum viewing distance n from your square pixel 16:9 1080p set and cut that distance to n/2, you would need a set with 4k resolution. n/4 would be 8k. The amount of information you can see goes down when you increase distance, and goes up the when you dicrease distance, following the point-source Inverse-Square Law ![]() Viewing Distance Chart Visible Resolution Limits (photobucket.com) Viewing Distance Thread ![]() See also the Delian Problem, Doubling the Cube. Back to Vewing Distance Last edited by U4K61; 05-21-2010 at 07:29 PM. |
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